Charging the iPod

Started by Wir, Apr 19, 2010, 15:50

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Wir

Apr 19, 2010, 15:50 Last Edit: Apr 19, 2010, 16:33 by Wir
Regarding this Paper.

I am using the Bridge ( http://toastlet.iamtoast.biz/a5 ) with this 5G iPod ( http://toastlet.iamtoast.biz/a4 ) and I've got the common "cannot charge using fw" issue.

Now, according to http://toastlet.iamtoast.biz/b9 there is this cryptic message:

Quote from: http://toastlet.iamtoast.biz/b9 cryptic paperUSB Data (+)
Pins 25 and 27 may be used in different manner. To force the iPod 5G to charge in any case, when USB Power 5 VDC (pin 23) is fed, 25 must be connected to 5V through a 10kOhm resistor, and 27 must be connected to the Ground (for example: pin 1) with a 10kOhm resistor.

iPod 5G can also be forced to charge by attaching the data + and the data - pins to the 5v via a 10k Ohm resistor ( BOTH PINS) and connecting pin 16 to the 5v (ground). (Confirmed working with iPod 5G 20GB)

To charge an iPhone 3G / iPod Touch 2nd gen or Ipod Classic (6th Gen), usb data- (25) should be at 2.8v, usb data+(27) should be at 2.0v. This can be done with a few simple resistors: 33k to +5v (23) and 22k to gnd(16) to obtain 2v and 33k to +5v and 47k to gnd to obtain 2.8v. This is a notification to the iphone that it is connected to the external charger and may drain amps from the usb.


But does connecting the USB + & - pins to resistors etc. not disable the function of "The Bridge"? Why? Why not?

Best regards

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